Tewtor.ai

Great question—let’s think it through together. What do you already know about how flight time depends on launch speed and angle in projectile motion (ignoring air resistance)?

Here’s the key simple idea: for a projectile that starts and lands at the same height with initial speed $v$ and launch angle $\theta$, the total time in the air is $T = \frac{2v \sin \theta}{g}$. So, at the same $v$, a higher angle (bigger $\sin \theta$) stays in the air longer. Meanwhile, the horizontal range is $R = \frac{v^2 \sin 2\theta}{g}$, which is largest near $\theta = 45^\circ$. So a “low, long” shot (smaller $\theta$, bigger $R$) usually has a smaller $T$, and a “high, short” shot (larger $\theta$, smaller $R$) usually has a larger $T$. Does that connection between angle, time, and range make sense so far?