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Got it! Here’s a quick math question for you:

If a particle’s de Broglie wavelength is given by $\lambda = \dfrac{h}{p}$ and its momentum is $p = 2.0 \times 10^{-24}\,\text{kg}\cdot\text{m/s}$, what is its wavelength? (Use $h = 6.626 \times 10^{-34}\,\text{J}\cdot\text{s}$.)