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Shared by Mohammed Usama2 views

QProblem

why did you divide by 2 first?

ASolution

When we solve a quadratic equation, any operation that multiplies every term by the same non‑zero number leaves the set of solutions unchanged.

In the equation

2x28x+6=02x^{2}-8x+6=0

the coefficients 2, –8, and 6 all share a common factor of 2. Dividing the entire equation by that greatest common factor (GCF) gives a simpler, “equivalent” equation:

2x228x2+62=0    x24x+3=0.\frac{2x^{2}}{2}-\frac{8x}{2}+\frac{6}{2}=0\;\Longrightarrow\;x^{2}-4x+3=0 .

Why this helps

  1. Smaller numbers – Working with 1, –4, and 3 is easier than with 2, –8, and 6 when we look for factors or apply the quadratic formula.
  2. Preserves solutions – Because we divided both sides of the equation by the same non‑zero constant (2), any value of xx that satisfies the original equation also satisfies the reduced one, and vice‑versa.
  3. No loss of information – The step does not discard any possible roots; it merely rewrites the same relationship in a more convenient form.

After the division, we can factor the quadratic:

x24x+3=(x1)(x3)=0,x^{2}-4x+3=(x-1)(x-3)=0,

which directly yields the solutions x=1x=1 and x=3x=3. If we had tried to factor the original form 2x28x+62x^{2}-8x+6 we would need to find two numbers whose product is 2×6=122\times6=12 and whose sum is 8-8; the numbers 6-6 and 2-2 work, but the algebra is a little messier. Dividing by the GCF streamlines the process.

So, dividing by 2 first is simply a convenient algebraic simplification that keeps the equation equivalent while making the subsequent steps easier.


Do you want a visual demonstration of how factoring works after the GCF is removed? I can provide an interactive quadratic‑explorer or another video if that would help. Let me know!

Shared on 8/1/2026

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